2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5

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Solution for 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5 equation: 



2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5

We move all terms to the left:

2k(-3k+4)+6(k^2+10)-(k(4k+8)-2k(2k+5)=0

We multiply parentheses

-6k^2+6k^2+8k-(k(4k+8)-2k(2k+5)+60=0

We add all the numbers together, and all the variables

8k-(k(4k+8)-2k(2k+5)+60=0

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